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4902112095 = 3517115316673
BaseRepresentation
bin1001001000011000…
…00100101101011111
3110122122012002121020
410210030010231133
540014420041340
62130233135223
7232323156666
oct44414045537
913578162536
104902112095
112096129411
12b4985a513
136017a755a
1434709dddd
151da56c9d0
hex124304b5f

4902112095 has 32 divisors (see below), whose sum is σ = 8312455872. Its totient is φ = 2458386432.

The previous prime is 4902112049. The next prime is 4902112097. The reversal of 4902112095 is 5902112094.

It is not a de Polignac number, because 4902112095 - 28 = 4902111839 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4902112097) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 285679 + ... + 302351.

It is an arithmetic number, because the mean of its divisors is an integer number (259764246).

Almost surely, 24902112095 is an apocalyptic number.

4902112095 is a deficient number, since it is larger than the sum of its proper divisors (3410343777).

4902112095 is a wasteful number, since it uses less digits than its factorization.

4902112095 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17851.

The product of its (nonzero) digits is 6480, while the sum is 33.

The square root of 4902112095 is about 70015.0847674985. The cubic root of 4902112095 is about 1698.7432574435.

Subtracting 4902112095 from its reverse (5902112094), we obtain a palindrome (999999999).

It can be divided in two parts, 49021 and 12095, that added together give a palindrome (61116).

The spelling of 4902112095 in words is "four billion, nine hundred two million, one hundred twelve thousand, ninety-five".

Divisors: 1 3 5 15 17 51 85 255 1153 3459 5765 16673 17295 19601 50019 58803 83365 98005 250095 283441 294015 850323 1417205 4251615 19223969 57671907 96119845 288359535 326807473 980422419 1634037365 4902112095