Base | Representation |
---|---|
bin | 101101101010000000… |
… | …010110001101101111 |
3 | 11200112111122022220021 |
4 | 231222000112031233 |
5 | 1300344404204033 |
6 | 34304303303011 |
7 | 3353560416601 |
oct | 555200261557 |
9 | 150474568807 |
10 | 49023116143 |
11 | 198772a8821 |
12 | 96018aaa67 |
13 | 4813567441 |
14 | 2530abd171 |
15 | 141dc2cb2d |
hex | b6a01636f |
49023116143 has 2 divisors, whose sum is σ = 49023116144. Its totient is φ = 49023116142.
The previous prime is 49023116137. The next prime is 49023116213. The reversal of 49023116143 is 34161132094.
49023116143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 49023116143 - 25 = 49023116111 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 49023116099 and 49023116108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49023111143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24511558071 + 24511558072.
It is an arithmetic number, because the mean of its divisors is an integer number (24511558072).
Almost surely, 249023116143 is an apocalyptic number.
49023116143 is a deficient number, since it is larger than the sum of its proper divisors (1).
49023116143 is an equidigital number, since it uses as much as digits as its factorization.
49023116143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 34.
The spelling of 49023116143 in words is "forty-nine billion, twenty-three million, one hundred sixteen thousand, one hundred forty-three".
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