Base | Representation |
---|---|
bin | 101101101010001001… |
… | …001011111111010111 |
3 | 11200112200000001210111 |
4 | 231222021023333113 |
5 | 1300401002333214 |
6 | 34304425103451 |
7 | 3353616211114 |
oct | 555211137727 |
9 | 150480001714 |
10 | 49025433559 |
11 | 19878640943 |
12 | 9602627b87 |
13 | 4813b991ab |
14 | 253112390b |
15 | 141e0395c4 |
hex | b6a24bfd7 |
49025433559 has 2 divisors, whose sum is σ = 49025433560. Its totient is φ = 49025433558.
The previous prime is 49025433517. The next prime is 49025433617. The reversal of 49025433559 is 95533452094.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 49025433559 - 233 = 40435498967 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49025433059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24512716779 + 24512716780.
It is an arithmetic number, because the mean of its divisors is an integer number (24512716780).
Almost surely, 249025433559 is an apocalyptic number.
49025433559 is a deficient number, since it is larger than the sum of its proper divisors (1).
49025433559 is an equidigital number, since it uses as much as digits as its factorization.
49025433559 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2916000, while the sum is 49.
The spelling of 49025433559 in words is "forty-nine billion, twenty-five million, four hundred thirty-three thousand, five hundred fifty-nine".
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