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4910717532053 is a prime number
BaseRepresentation
bin100011101110101110110…
…0100101111011110010101
3122101110102100101211020002
41013131131210233132111
51120424122142011203
614235541423221045
71014534105206564
oct107353544573625
918343370354202
104910717532053
11162369502a973
12673891447785
13298103b0c388
1412d973ca7bdb
1587b1437bd88
hex4775d92f795

4910717532053 has 2 divisors, whose sum is σ = 4910717532054. Its totient is φ = 4910717532052.

The previous prime is 4910717532023. The next prime is 4910717532059. The reversal of 4910717532053 is 3502357170194.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4726245564049 + 184471968004 = 2173993^2 + 429502^2 .

It is a cyclic number.

It is not a de Polignac number, because 4910717532053 - 230 = 4909643790229 is a prime.

It is a super-2 number, since 2×49107175320532 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4910717531989 and 4910717532007.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4910717532059) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2455358766026 + 2455358766027.

It is an arithmetic number, because the mean of its divisors is an integer number (2455358766027).

Almost surely, 24910717532053 is an apocalyptic number.

It is an amenable number.

4910717532053 is a deficient number, since it is larger than the sum of its proper divisors (1).

4910717532053 is an equidigital number, since it uses as much as digits as its factorization.

4910717532053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 793800, while the sum is 47.

The spelling of 4910717532053 in words is "four trillion, nine hundred ten billion, seven hundred seventeen million, five hundred thirty-two thousand, fifty-three".