4912580611781 has 2 divisors, whose sum is σ = 4912580611782. Its totient is φ = 4912580611780.

The previous prime is 4912580611759. The next prime is 4912580611801. The reversal of 4912580611781 is 1871160852194.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3251407623556 + 1661172988225 = 1803166^2 + 1288865^2 .

It is a cyclic number.

It is not a de Polignac number, because 4912580611781 - 2¹⁸ = 4912580349637 is a prime.

It is a super-3 number, since 3×4912580611781³ (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4912580611721) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2456290305890 + 2456290305891.

It is an arithmetic number, because the mean of its divisors is an integer number (2456290305891).

Almost surely, 2^{4912580611781} is an apocalyptic number.

It is an amenable number.

4912580611781 is a deficient number, since it is larger than the sum of its proper divisors (1).

4912580611781 is an equidigital number, since it uses as much as digits as its factorization.

4912580611781 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 967680, while the sum is 53.

The spelling of 4912580611781 in words is "four trillion, nine hundred twelve billion, five hundred eighty million, six hundred eleven thousand, seven hundred eighty-one".