Base | Representation |
---|---|
bin | 101101110000101100… |
… | …011001010010001011 |
3 | 11200211022210012100202 |
4 | 231300230121102023 |
5 | 1301112120420342 |
6 | 34323352322415 |
7 | 3356422245212 |
oct | 556054312213 |
9 | 150738705322 |
10 | 49135326347 |
11 | 19924679a28 |
12 | 96333a340b |
13 | 4830894803 |
14 | 254196c079 |
15 | 14289e5332 |
hex | b70b1948b |
49135326347 has 2 divisors, whose sum is σ = 49135326348. Its totient is φ = 49135326346.
The previous prime is 49135326343. The next prime is 49135326349. The reversal of 49135326347 is 74362353194.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 49135326347 - 22 = 49135326343 is a prime.
Together with 49135326349, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (49135326343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24567663173 + 24567663174.
It is an arithmetic number, because the mean of its divisors is an integer number (24567663174).
Almost surely, 249135326347 is an apocalyptic number.
49135326347 is a deficient number, since it is larger than the sum of its proper divisors (1).
49135326347 is an equidigital number, since it uses as much as digits as its factorization.
49135326347 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1632960, while the sum is 47.
The spelling of 49135326347 in words is "forty-nine billion, one hundred thirty-five million, three hundred twenty-six thousand, three hundred forty-seven".
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