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491514503 is a prime number
BaseRepresentation
bin11101010010111…
…110101010000111
31021020212112010212
4131102332222013
52001311431003
6120434510035
715115542614
oct3522765207
91236775125
10491514503
112324a1137
1211873531b
137aaa39ac
14493c750b
152d23ddd8
hex1d4bea87

491514503 has 2 divisors, whose sum is σ = 491514504. Its totient is φ = 491514502.

The previous prime is 491514487. The next prime is 491514509. The reversal of 491514503 is 305415194.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 491514503 - 24 = 491514487 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 491514503.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (491514509) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 245757251 + 245757252.

It is an arithmetic number, because the mean of its divisors is an integer number (245757252).

Almost surely, 2491514503 is an apocalyptic number.

491514503 is a deficient number, since it is larger than the sum of its proper divisors (1).

491514503 is an equidigital number, since it uses as much as digits as its factorization.

491514503 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10800, while the sum is 32.

The square root of 491514503 is about 22170.1263640963. The cubic root of 491514503 is about 789.1849217679.

Adding to 491514503 its reverse (305415194), we get a palindrome (796929697).

The spelling of 491514503 in words is "four hundred ninety-one million, five hundred fourteen thousand, five hundred three".