Base | Representation |
---|---|
bin | 1110010101001011001… |
… | …11011011011000010111 |
3 | 1202001222112121000121012 |
4 | 13022211213123120113 |
5 | 31031421120120101 |
6 | 1014112504442435 |
7 | 50401152102446 |
oct | 7124547333027 |
9 | 1661875530535 |
10 | 492404848151 |
11 | 17a9117774a7 |
12 | 7b52147941b |
13 | 37583755b98 |
14 | 19b92622d5d |
15 | cc1de57bbb |
hex | 72a59db617 |
492404848151 has 2 divisors, whose sum is σ = 492404848152. Its totient is φ = 492404848150.
The previous prime is 492404848099. The next prime is 492404848153. The reversal of 492404848151 is 151848404294.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 492404848151 - 26 = 492404848087 is a prime.
Together with 492404848153, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 492404848151.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (492404848153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 246202424075 + 246202424076.
It is an arithmetic number, because the mean of its divisors is an integer number (246202424076).
Almost surely, 2492404848151 is an apocalyptic number.
492404848151 is a deficient number, since it is larger than the sum of its proper divisors (1).
492404848151 is an equidigital number, since it uses as much as digits as its factorization.
492404848151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1474560, while the sum is 50.
The spelling of 492404848151 in words is "four hundred ninety-two billion, four hundred four million, eight hundred forty-eight thousand, one hundred fifty-one".
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