Base | Representation |
---|---|
bin | 101101110111110100… |
… | …111100111000110111 |
3 | 11201010122222202020222 |
4 | 231313310330320313 |
5 | 1301333240303342 |
6 | 34343305444555 |
7 | 3362404450541 |
oct | 556764747067 |
9 | 151118882228 |
10 | 49255009847 |
11 | 19986194a0a |
12 | 96674a075b |
13 | 484c60a654 |
14 | 2553804691 |
15 | 1434286ed2 |
hex | b77d3ce37 |
49255009847 has 2 divisors, whose sum is σ = 49255009848. Its totient is φ = 49255009846.
The previous prime is 49255009831. The next prime is 49255009861. The reversal of 49255009847 is 74890055294.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 49255009847 - 24 = 49255009831 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49255009807) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24627504923 + 24627504924.
It is an arithmetic number, because the mean of its divisors is an integer number (24627504924).
Almost surely, 249255009847 is an apocalyptic number.
49255009847 is a deficient number, since it is larger than the sum of its proper divisors (1).
49255009847 is an equidigital number, since it uses as much as digits as its factorization.
49255009847 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3628800, while the sum is 53.
The spelling of 49255009847 in words is "forty-nine billion, two hundred fifty-five million, nine thousand, eight hundred forty-seven".
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