Base | Representation |
---|---|
bin | 10110011100010101001101… |
… | …11000000010100010001101 |
3 | 20110202000001220210112202021 |
4 | 23032022212320002202031 |
5 | 22432040320312024331 |
6 | 252543552301530141 |
7 | 13252363630661413 |
oct | 1316124670024215 |
9 | 213660056715667 |
10 | 49351973939341 |
11 | 147a806675a377 |
12 | 56508b0273951 |
13 | 216cb42c771c8 |
14 | c28910c672b3 |
15 | 5a8b588b3211 |
hex | 2ce2a6e0288d |
49351973939341 has 2 divisors, whose sum is σ = 49351973939342. Its totient is φ = 49351973939340.
The previous prime is 49351973939311. The next prime is 49351973939347. The reversal of 49351973939341 is 14393937915394.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 32563115088100 + 16788858851241 = 5706410^2 + 4097421^2 .
It is a cyclic number.
It is not a de Polignac number, because 49351973939341 - 25 = 49351973939309 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49351973939347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24675986969670 + 24675986969671.
It is an arithmetic number, because the mean of its divisors is an integer number (24675986969671).
Almost surely, 249351973939341 is an apocalyptic number.
It is an amenable number.
49351973939341 is a deficient number, since it is larger than the sum of its proper divisors (1).
49351973939341 is an equidigital number, since it uses as much as digits as its factorization.
49351973939341 is an evil number, because the sum of its binary digits is even.
The product of its digits is 297606960, while the sum is 70.
The spelling of 49351973939341 in words is "forty-nine trillion, three hundred fifty-one billion, nine hundred seventy-three million, nine hundred thirty-nine thousand, three hundred forty-one".
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