Base | Representation |
---|---|
bin | 10110011100010101001101… |
… | …11000000010100001101111 |
3 | 20110202000001220210112201011 |
4 | 23032022212320002201233 |
5 | 22432040320312024221 |
6 | 252543552301530051 |
7 | 13252363630661341 |
oct | 1316124670024157 |
9 | 213660056715634 |
10 | 49351973939311 |
11 | 147a806675a34a |
12 | 56508b0273927 |
13 | 216cb42c771a4 |
14 | c28910c67291 |
15 | 5a8b588b31e1 |
hex | 2ce2a6e0286f |
49351973939311 has 2 divisors, whose sum is σ = 49351973939312. Its totient is φ = 49351973939310.
The previous prime is 49351973939309. The next prime is 49351973939341. The reversal of 49351973939311 is 11393937915394.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 49351973939311 - 21 = 49351973939309 is a prime.
It is a super-2 number, since 2×493519739393112 (a number of 28 digits) contains 22 as substring.
Together with 49351973939309, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49351973939341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24675986969655 + 24675986969656.
It is an arithmetic number, because the mean of its divisors is an integer number (24675986969656).
Almost surely, 249351973939311 is an apocalyptic number.
49351973939311 is a deficient number, since it is larger than the sum of its proper divisors (1).
49351973939311 is an equidigital number, since it uses as much as digits as its factorization.
49351973939311 is an evil number, because the sum of its binary digits is even.
The product of its digits is 74401740, while the sum is 67.
The spelling of 49351973939311 in words is "forty-nine trillion, three hundred fifty-one billion, nine hundred seventy-three million, nine hundred thirty-nine thousand, three hundred eleven".
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