Base | Representation |
---|---|
bin | 100011111011100011001… |
… | …0101011101010000101011 |
3 | 122111002110210001212111021 |
4 | 1013313012111131100223 |
5 | 1121402011200433442 |
6 | 14300333131113311 |
7 | 1016530212246013 |
oct | 107670625352053 |
9 | 18432423055437 |
10 | 4938244936747 |
11 | 1634330588501 |
12 | 6790942a2837 |
13 | 29a89cb4b915 |
14 | 131025b96c43 |
15 | 886c5d8ee67 |
hex | 47dc655d42b |
4938244936747 has 2 divisors, whose sum is σ = 4938244936748. Its totient is φ = 4938244936746.
The previous prime is 4938244936739. The next prime is 4938244936817. The reversal of 4938244936747 is 7476394428394.
It is a happy number.
It is an a-pointer prime, because the next prime (4938244936817) can be obtained adding 4938244936747 to its sum of digits (70).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4938244936747 - 23 = 4938244936739 is a prime.
It is not a weakly prime, because it can be changed into another prime (4908244936747) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2469122468373 + 2469122468374.
It is an arithmetic number, because the mean of its divisors is an integer number (2469122468374).
Almost surely, 24938244936747 is an apocalyptic number.
4938244936747 is a deficient number, since it is larger than the sum of its proper divisors (1).
4938244936747 is an equidigital number, since it uses as much as digits as its factorization.
4938244936747 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 877879296, while the sum is 70.
The spelling of 4938244936747 in words is "four trillion, nine hundred thirty-eight billion, two hundred forty-four million, nine hundred thirty-six thousand, seven hundred forty-seven".
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