Base | Representation |
---|---|
bin | 11101011100100… |
… | …101100001111101 |
3 | 1021102121110220022 |
4 | 131130211201331 |
5 | 2002433024041 |
6 | 121004501525 |
7 | 15146132336 |
oct | 3534454175 |
9 | 1242543808 |
10 | 494033021 |
11 | 233961359 |
12 | 11954a8a5 |
13 | 7b476141 |
14 | 4988128d |
15 | 2d58a24b |
hex | 1d72587d |
494033021 has 2 divisors, whose sum is σ = 494033022. Its totient is φ = 494033020.
The previous prime is 494032967. The next prime is 494033047. The reversal of 494033021 is 120330494.
It is an a-pointer prime, because the next prime (494033047) can be obtained adding 494033021 to its sum of digits (26).
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 303979225 + 190053796 = 17435^2 + 13786^2 .
It is a cyclic number.
It is not a de Polignac number, because 494033021 - 222 = 489838717 is a prime.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (494033921) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 247016510 + 247016511.
It is an arithmetic number, because the mean of its divisors is an integer number (247016511).
Almost surely, 2494033021 is an apocalyptic number.
It is an amenable number.
494033021 is a deficient number, since it is larger than the sum of its proper divisors (1).
494033021 is an equidigital number, since it uses as much as digits as its factorization.
494033021 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 26.
The square root of 494033021 is about 22226.8536009936. The cubic root of 494033021 is about 790.5305526511.
The spelling of 494033021 in words is "four hundred ninety-four million, thirty-three thousand, twenty-one".
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