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494434434493 is a prime number
BaseRepresentation
bin1110011000111101001…
…01101011110110111101
31202021012222121200122201
413030132211223312331
531100100203400433
61015050125511501
750502355231006
oct7143645536675
91667188550581
10494434434493
1118076339178a
127b9a9112591
133781808bb4c
1419d05dc01ad
15ccdc211a7d
hex731e96bdbd

494434434493 has 2 divisors, whose sum is σ = 494434434494. Its totient is φ = 494434434492.

The previous prime is 494434434427. The next prime is 494434434509. The reversal of 494434434493 is 394434434494.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 468406097604 + 26028336889 = 684402^2 + 161333^2 .

It is a cyclic number.

It is not a de Polignac number, because 494434434493 - 29 = 494434433981 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (494434434413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 247217217246 + 247217217247.

It is an arithmetic number, because the mean of its divisors is an integer number (247217217247).

Almost surely, 2494434434493 is an apocalyptic number.

It is an amenable number.

494434434493 is a deficient number, since it is larger than the sum of its proper divisors (1).

494434434493 is an equidigital number, since it uses as much as digits as its factorization.

494434434493 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 35831808, while the sum is 55.

Subtracting from 494434434493 its reverse (394434434494), we obtain a palindrome (99999999999).

The spelling of 494434434493 in words is "four hundred ninety-four billion, four hundred thirty-four million, four hundred thirty-four thousand, four hundred ninety-three".