Base | Representation |
---|---|
bin | 101110000101011011… |
… | …111001110100011111 |
3 | 11201201120121100100202 |
4 | 232011123321310133 |
5 | 1302320212342303 |
6 | 34422103214115 |
7 | 3401146214531 |
oct | 560533716437 |
9 | 151646540322 |
10 | 49483324703 |
11 | 19a9305727a |
12 | 970ba4733b |
13 | 48879c98b7 |
14 | 2575c77851 |
15 | 1449335c88 |
hex | b856f9d1f |
49483324703 has 2 divisors, whose sum is σ = 49483324704. Its totient is φ = 49483324702.
The previous prime is 49483324589. The next prime is 49483324717. The reversal of 49483324703 is 30742338494.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 49483324703 - 210 = 49483323679 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49483324733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24741662351 + 24741662352.
It is an arithmetic number, because the mean of its divisors is an integer number (24741662352).
Almost surely, 249483324703 is an apocalyptic number.
49483324703 is a deficient number, since it is larger than the sum of its proper divisors (1).
49483324703 is an equidigital number, since it uses as much as digits as its factorization.
49483324703 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1741824, while the sum is 47.
The spelling of 49483324703 in words is "forty-nine billion, four hundred eighty-three million, three hundred twenty-four thousand, seven hundred three".
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