Base | Representation |
---|---|
bin | 101110000101011011… |
… | …111001110101110101 |
3 | 11201201120121100110221 |
4 | 232011123321311311 |
5 | 1302320212343124 |
6 | 34422103214341 |
7 | 3401146215013 |
oct | 560533716565 |
9 | 151646540427 |
10 | 49483324789 |
11 | 19a93057348 |
12 | 970ba473b1 |
13 | 48879c9952 |
14 | 2575c778b3 |
15 | 1449335ce4 |
hex | b856f9d75 |
49483324789 has 2 divisors, whose sum is σ = 49483324790. Its totient is φ = 49483324788.
The previous prime is 49483324763. The next prime is 49483324817. The reversal of 49483324789 is 98742338494.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 49259583025 + 223741764 = 221945^2 + 14958^2 .
It is a cyclic number.
It is not a de Polignac number, because 49483324789 - 211 = 49483322741 is a prime.
It is a super-3 number, since 3×494833247893 (a number of 33 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49483324739) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24741662394 + 24741662395.
It is an arithmetic number, because the mean of its divisors is an integer number (24741662395).
Almost surely, 249483324789 is an apocalyptic number.
It is an amenable number.
49483324789 is a deficient number, since it is larger than the sum of its proper divisors (1).
49483324789 is an equidigital number, since it uses as much as digits as its factorization.
49483324789 is an evil number, because the sum of its binary digits is even.
The product of its digits is 41803776, while the sum is 61.
The spelling of 49483324789 in words is "forty-nine billion, four hundred eighty-three million, three hundred twenty-four thousand, seven hundred eighty-nine".
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