Base | Representation |
---|---|
bin | 1110011001110110111… |
… | …01101011111100110111 |
3 | 1202022110202011220211011 |
4 | 13030323131223330313 |
5 | 31102043213030413 |
6 | 1015210153053051 |
7 | 50520360020536 |
oct | 7147335537467 |
9 | 1668422156734 |
10 | 494918876983 |
11 | 180991892583 |
12 | 7bb033b7187 |
13 | 378945578cb |
14 | 19d5048631d |
15 | cd19a0533d |
hex | 733b76bf37 |
494918876983 has 2 divisors, whose sum is σ = 494918876984. Its totient is φ = 494918876982.
The previous prime is 494918876981. The next prime is 494918877073. The reversal of 494918876983 is 389678819494.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 494918876983 - 21 = 494918876981 is a prime.
It is a super-2 number, since 2×4949188769832 (a number of 24 digits) contains 22 as substring.
Together with 494918876981, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (494918876981) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 247459438491 + 247459438492.
It is an arithmetic number, because the mean of its divisors is an integer number (247459438492).
Almost surely, 2494918876983 is an apocalyptic number.
494918876983 is a deficient number, since it is larger than the sum of its proper divisors (1).
494918876983 is an equidigital number, since it uses as much as digits as its factorization.
494918876983 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 752467968, while the sum is 76.
The spelling of 494918876983 in words is "four hundred ninety-four billion, nine hundred eighteen million, eight hundred seventy-six thousand, nine hundred eighty-three".
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