Base | Representation |
---|---|
bin | 1110011011011000101… |
… | …10101101000010010000 |
3 | 1202101120220122002102112 |
4 | 13031230112231002100 |
5 | 31110233204130000 |
6 | 1015423414004452 |
7 | 50546610036002 |
oct | 7155426550220 |
9 | 1671526562375 |
10 | 495739130000 |
11 | 1812728a6834 |
12 | 800b2046728 |
13 | 3799547c11a |
14 | 19dcb3a4372 |
15 | cd66a2d235 |
hex | 736c5ad090 |
495739130000 has 50 divisors (see below), whose sum is σ = 1200234031854. Its totient is φ = 198295648000.
The previous prime is 495739129999. The next prime is 495739130039. The reversal of 495739130000 is 31937594.
It can be written as a sum of positive squares in 5 ways, for example, as 66300070144 + 429439059856 = 257488^2 + 655316^2 .
It is a tau number, because it is divible by the number of its divisors (50).
It is a self number, because there is not a number n which added to its sum of digits gives 495739130000.
It is an unprimeable number.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 24776957 + ... + 24796956.
Almost surely, 2495739130000 is an apocalyptic number.
495739130000 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
495739130000 is an abundant number, since it is smaller than the sum of its proper divisors (704494901854).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
495739130000 is an equidigital number, since it uses as much as digits as its factorization.
495739130000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 49573941 (or 49573920 counting only the distinct ones).
The product of its (nonzero) digits is 102060, while the sum is 41.
The spelling of 495739130000 in words is "four hundred ninety-five billion, seven hundred thirty-nine million, one hundred thirty thousand".
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