Base | Representation |
---|---|
bin | 1001001111011101… |
… | …01010011010001101 |
3 | 110210202221212122122 |
4 | 10213232222122031 |
5 | 40130121323203 |
6 | 2140154222325 |
7 | 233644101542 |
oct | 44756523215 |
9 | 13722855578 |
10 | 4961511053 |
11 | 2116709764 |
12 | b657249a5 |
13 | 610ba3a75 |
14 | 350d22bc9 |
15 | 1e08a2538 |
hex | 127baa68d |
4961511053 has 2 divisors, whose sum is σ = 4961511054. Its totient is φ = 4961511052.
The previous prime is 4961511029. The next prime is 4961511077. The reversal of 4961511053 is 3501151694.
It is a balanced prime because it is at equal distance from previous prime (4961511029) and next prime (4961511077).
It can be written as a sum of positive squares in only one way, i.e., 4250648809 + 710862244 = 65197^2 + 26662^2 .
It is a cyclic number.
It is not a de Polignac number, because 4961511053 - 214 = 4961494669 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4961511853) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2480755526 + 2480755527.
It is an arithmetic number, because the mean of its divisors is an integer number (2480755527).
Almost surely, 24961511053 is an apocalyptic number.
It is an amenable number.
4961511053 is a deficient number, since it is larger than the sum of its proper divisors (1).
4961511053 is an equidigital number, since it uses as much as digits as its factorization.
4961511053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16200, while the sum is 35.
The square root of 4961511053 is about 70437.9943851328. The cubic root of 4961511053 is about 1705.5769615676.
The spelling of 4961511053 in words is "four billion, nine hundred sixty-one million, five hundred eleven thousand, fifty-three".
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