Base | Representation |
---|---|
bin | 101110001101100101… |
… | …110101100000110111 |
3 | 11202002010001121012202 |
4 | 232031211311200313 |
5 | 1303110224134411 |
6 | 34443431535115 |
7 | 3404430166235 |
oct | 561545654067 |
9 | 152063047182 |
10 | 49620146231 |
11 | 1a053308317 |
12 | 974982a49b |
13 | 48aa163296 |
14 | 258a0d1955 |
15 | 145636083b |
hex | b8d975837 |
49620146231 has 2 divisors, whose sum is σ = 49620146232. Its totient is φ = 49620146230.
The previous prime is 49620146209. The next prime is 49620146239. The reversal of 49620146231 is 13264102694.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 49620146231 - 222 = 49615951927 is a prime.
It is a super-3 number, since 3×496201462313 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49620146239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24810073115 + 24810073116.
It is an arithmetic number, because the mean of its divisors is an integer number (24810073116).
Almost surely, 249620146231 is an apocalyptic number.
49620146231 is a deficient number, since it is larger than the sum of its proper divisors (1).
49620146231 is an equidigital number, since it uses as much as digits as its factorization.
49620146231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 62208, while the sum is 38.
The spelling of 49620146231 in words is "forty-nine billion, six hundred twenty million, one hundred forty-six thousand, two hundred thirty-one".
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