Base | Representation |
---|---|
bin | 101110001101100110… |
… | …001010000101100111 |
3 | 11202002010012212210221 |
4 | 232031212022011213 |
5 | 1303110234334003 |
6 | 34443433425211 |
7 | 3404431000024 |
oct | 561546120547 |
9 | 152063185727 |
10 | 49620230503 |
11 | 1a053365668 |
12 | 974986b207 |
13 | 48aa19274c |
14 | 258a11454b |
15 | 145637a7bd |
hex | b8d98a167 |
49620230503 has 2 divisors, whose sum is σ = 49620230504. Its totient is φ = 49620230502.
The previous prime is 49620230477. The next prime is 49620230551. The reversal of 49620230503 is 30503202694.
49620230503 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 49620230503 - 221 = 49618133351 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49620230573) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24810115251 + 24810115252.
It is an arithmetic number, because the mean of its divisors is an integer number (24810115252).
Almost surely, 249620230503 is an apocalyptic number.
49620230503 is a deficient number, since it is larger than the sum of its proper divisors (1).
49620230503 is an equidigital number, since it uses as much as digits as its factorization.
49620230503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 38880, while the sum is 34.
The spelling of 49620230503 in words is "forty-nine billion, six hundred twenty million, two hundred thirty thousand, five hundred three".
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