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49628134400 = 2105213211471
BaseRepresentation
bin101110001110000100…
…010011110000000000
311202002200002102220212
4232032010103300000
51303114300300100
634444315053252
73404555116325
oct561604236000
9152080072825
1049628134400
111a057873a09
129750441228
1348ab9cc200
14258b1b0b4c
151456ddc635
hexb8e113c00

49628134400 has 198 divisors, whose sum is σ = 133220102832. Its totient is φ = 18322636800.

The previous prime is 49628134399. The next prime is 49628134433. The reversal of 49628134400 is 443182694.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 4320665 + ... + 4332135.

Almost surely, 249628134400 is an apocalyptic number.

49628134400 is a gapful number since it is divisible by the number (40) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 49628134400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (66610051416).

49628134400 is an abundant number, since it is smaller than the sum of its proper divisors (83591968432).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

49628134400 is a wasteful number, since it uses less digits than its factorization.

49628134400 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11527 (or 11491 counting only the distinct ones).

The product of its (nonzero) digits is 165888, while the sum is 41.

The spelling of 49628134400 in words is "forty-nine billion, six hundred twenty-eight million, one hundred thirty-four thousand, four hundred".