Base | Representation |
---|---|
bin | 101110001110000100… |
… | …010011110000100001 |
3 | 11202002200002102222002 |
4 | 232032010103300201 |
5 | 1303114300300213 |
6 | 34444315053345 |
7 | 3404555116403 |
oct | 561604236041 |
9 | 152080072862 |
10 | 49628134433 |
11 | 1a057873a39 |
12 | 9750441255 |
13 | 48ab9cc227 |
14 | 258b1b0b73 |
15 | 1456ddc658 |
hex | b8e113c21 |
49628134433 has 2 divisors, whose sum is σ = 49628134434. Its totient is φ = 49628134432.
The previous prime is 49628134399. The next prime is 49628134469. The reversal of 49628134433 is 33443182694.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 44847379984 + 4780754449 = 211772^2 + 69143^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-49628134433 is a prime.
It is not a weakly prime, because it can be changed into another prime (49628134033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24814067216 + 24814067217.
It is an arithmetic number, because the mean of its divisors is an integer number (24814067217).
Almost surely, 249628134433 is an apocalyptic number.
It is an amenable number.
49628134433 is a deficient number, since it is larger than the sum of its proper divisors (1).
49628134433 is an equidigital number, since it uses as much as digits as its factorization.
49628134433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1492992, while the sum is 47.
The spelling of 49628134433 in words is "forty-nine billion, six hundred twenty-eight million, one hundred thirty-four thousand, four hundred thirty-three".
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