Base | Representation |
---|---|
bin | 101110001110000100… |
… | …010011101111111111 |
3 | 11202002200002102220211 |
4 | 232032010103233333 |
5 | 1303114300300044 |
6 | 34444315053251 |
7 | 3404555116324 |
oct | 561604235777 |
9 | 152080072824 |
10 | 49628134399 |
11 | 1a057873a08 |
12 | 9750441227 |
13 | 48ab9cc1cc |
14 | 258b1b0b4b |
15 | 1456ddc634 |
hex | b8e113bff |
49628134399 has 2 divisors, whose sum is σ = 49628134400. Its totient is φ = 49628134398.
The previous prime is 49628134397. The next prime is 49628134433. The reversal of 49628134399 is 99343182694.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 49628134399 - 21 = 49628134397 is a prime.
Together with 49628134397, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49628134397) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24814067199 + 24814067200.
It is an arithmetic number, because the mean of its divisors is an integer number (24814067200).
Almost surely, 249628134399 is an apocalyptic number.
49628134399 is a deficient number, since it is larger than the sum of its proper divisors (1).
49628134399 is an equidigital number, since it uses as much as digits as its factorization.
49628134399 is an evil number, because the sum of its binary digits is even.
The product of its digits is 10077696, while the sum is 58.
The spelling of 49628134399 in words is "forty-nine billion, six hundred twenty-eight million, one hundred thirty-four thousand, three hundred ninety-nine".
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