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49678042153 is a prime number
BaseRepresentation
bin101110010001000010…
…101100010000101001
311202020011000000111011
4232101002230100221
51303220034322103
634453300503521
73406032251065
oct562102542051
9152204000434
1049678042153
111a082a61393
1297650aaba1
1348b915461c
142593a82aa5
15145b499d6d
hexb910ac429

49678042153 has 2 divisors, whose sum is σ = 49678042154. Its totient is φ = 49678042152.

The previous prime is 49678042151. The next prime is 49678042199. The reversal of 49678042153 is 35124087694.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 49638503209 + 39538944 = 222797^2 + 6288^2 .

It is a cyclic number.

It is not a de Polignac number, because 49678042153 - 21 = 49678042151 is a prime.

Together with 49678042151, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 49678042097 and 49678042106.

It is not a weakly prime, because it can be changed into another prime (49678042151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24839021076 + 24839021077.

It is an arithmetic number, because the mean of its divisors is an integer number (24839021077).

It is a 1-persistent number, because it is pandigital, but 2⋅49678042153 = 99356084306 is not.

Almost surely, 249678042153 is an apocalyptic number.

It is an amenable number.

49678042153 is a deficient number, since it is larger than the sum of its proper divisors (1).

49678042153 is an equidigital number, since it uses as much as digits as its factorization.

49678042153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1451520, while the sum is 49.

The spelling of 49678042153 in words is "forty-nine billion, six hundred seventy-eight million, forty-two thousand, one hundred fifty-three".