Base | Representation |
---|---|
bin | 10110100110000111001010… |
… | …01100101111110011110111 |
3 | 20111221010111000221000210001 |
4 | 23103003211030233303313 |
5 | 23003042034403113101 |
6 | 253402210421212131 |
7 | 13315561425622144 |
oct | 1323034514576367 |
9 | 214833430830701 |
10 | 49688027004151 |
11 | 149176349748a8 |
12 | 56a5a57861047 |
13 | 219573a226053 |
14 | c3acb02b73cb |
15 | 5b27762b6901 |
hex | 2d30e532fcf7 |
49688027004151 has 2 divisors, whose sum is σ = 49688027004152. Its totient is φ = 49688027004150.
The previous prime is 49688027004137. The next prime is 49688027004173. The reversal of 49688027004151 is 15140072088694.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 49688027004151 - 225 = 49687993449719 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 49688027004092 and 49688027004101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49688027004751) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24844013502075 + 24844013502076.
It is an arithmetic number, because the mean of its divisors is an integer number (24844013502076).
Almost surely, 249688027004151 is an apocalyptic number.
49688027004151 is a deficient number, since it is larger than the sum of its proper divisors (1).
49688027004151 is an equidigital number, since it uses as much as digits as its factorization.
49688027004151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3870720, while the sum is 55.
The spelling of 49688027004151 in words is "forty-nine trillion, six hundred eighty-eight billion, twenty-seven million, four thousand, one hundred fifty-one".
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