Base | Representation |
---|---|
bin | 10110100110000111001010… |
… | …01100101111110100001101 |
3 | 20111221010111000221000210212 |
4 | 23103003211030233310031 |
5 | 23003042034403113143 |
6 | 253402210421212205 |
7 | 13315561425622205 |
oct | 1323034514576415 |
9 | 214833430830725 |
10 | 49688027004173 |
11 | 14917634974918 |
12 | 56a5a57861065 |
13 | 219573a22606c |
14 | c3acb02b7405 |
15 | 5b27762b6918 |
hex | 2d30e532fd0d |
49688027004173 has 2 divisors, whose sum is σ = 49688027004174. Its totient is φ = 49688027004172.
The previous prime is 49688027004151. The next prime is 49688027004197. The reversal of 49688027004173 is 37140072088694.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 33396817884004 + 16291209120169 = 5778998^2 + 4036237^2 .
It is a cyclic number.
It is not a de Polignac number, because 49688027004173 - 214 = 49688026987789 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49688027204173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24844013502086 + 24844013502087.
It is an arithmetic number, because the mean of its divisors is an integer number (24844013502087).
Almost surely, 249688027004173 is an apocalyptic number.
It is an amenable number.
49688027004173 is a deficient number, since it is larger than the sum of its proper divisors (1).
49688027004173 is an equidigital number, since it uses as much as digits as its factorization.
49688027004173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16257024, while the sum is 59.
The spelling of 49688027004173 in words is "forty-nine trillion, six hundred eighty-eight billion, twenty-seven million, four thousand, one hundred seventy-three".
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