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49688027004173 is a prime number
BaseRepresentation
bin10110100110000111001010…
…01100101111110100001101
320111221010111000221000210212
423103003211030233310031
523003042034403113143
6253402210421212205
713315561425622205
oct1323034514576415
9214833430830725
1049688027004173
1114917634974918
1256a5a57861065
13219573a22606c
14c3acb02b7405
155b27762b6918
hex2d30e532fd0d

49688027004173 has 2 divisors, whose sum is σ = 49688027004174. Its totient is φ = 49688027004172.

The previous prime is 49688027004151. The next prime is 49688027004197. The reversal of 49688027004173 is 37140072088694.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 33396817884004 + 16291209120169 = 5778998^2 + 4036237^2 .

It is a cyclic number.

It is not a de Polignac number, because 49688027004173 - 214 = 49688026987789 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (49688027204173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24844013502086 + 24844013502087.

It is an arithmetic number, because the mean of its divisors is an integer number (24844013502087).

Almost surely, 249688027004173 is an apocalyptic number.

It is an amenable number.

49688027004173 is a deficient number, since it is larger than the sum of its proper divisors (1).

49688027004173 is an equidigital number, since it uses as much as digits as its factorization.

49688027004173 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16257024, while the sum is 59.

The spelling of 49688027004173 in words is "forty-nine trillion, six hundred eighty-eight billion, twenty-seven million, four thousand, one hundred seventy-three".