Base | Representation |
---|---|
bin | 1001010000100000… |
… | …11110000100011111 |
3 | 110211101122010111222 |
4 | 10220100132010133 |
5 | 40134403422112 |
6 | 2141112203555 |
7 | 234112322366 |
oct | 45020360437 |
9 | 13741563458 |
10 | 4970373407 |
11 | 212071211a |
12 | b686995bb |
13 | 61298786c |
14 | 35218c7dd |
15 | 1e1553372 |
hex | 12841e11f |
4970373407 has 2 divisors, whose sum is σ = 4970373408. Its totient is φ = 4970373406.
The previous prime is 4970373349. The next prime is 4970373409. The reversal of 4970373407 is 7043730794.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4970373407 - 28 = 4970373151 is a prime.
It is a super-2 number, since 2×49703734072 = 49409223610025575298, which contains 22 as substring.
Together with 4970373409, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4970373409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2485186703 + 2485186704.
It is an arithmetic number, because the mean of its divisors is an integer number (2485186704).
Almost surely, 24970373407 is an apocalyptic number.
4970373407 is a deficient number, since it is larger than the sum of its proper divisors (1).
4970373407 is an equidigital number, since it uses as much as digits as its factorization.
4970373407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 444528, while the sum is 44.
The square root of 4970373407 is about 70500.8752215176. The cubic root of 4970373407 is about 1706.5918698443.
The spelling of 4970373407 in words is "four billion, nine hundred seventy million, three hundred seventy-three thousand, four hundred seven".
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