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49712069573 is a prime number
BaseRepresentation
bin101110010011000100…
…011111101111000101
311202022112000210022222
4232103010133233011
51303302242211243
634500514102125
73406624422305
oct562304375705
9152275023288
1049712069573
111a0a0192721
12977457a945
1348c32097aa
1425983bd605
15145e46c168
hexb9311fbc5

49712069573 has 2 divisors, whose sum is σ = 49712069574. Its totient is φ = 49712069572.

The previous prime is 49712069513. The next prime is 49712069591. The reversal of 49712069573 is 37596021794.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 49712053444 + 16129 = 222962^2 + 127^2 .

It is a cyclic number.

It is not a de Polignac number, because 49712069573 - 212 = 49712065477 is a prime.

It is a super-2 number, since 2×497120695732 (a number of 22 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (49712069513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24856034786 + 24856034787.

It is an arithmetic number, because the mean of its divisors is an integer number (24856034787).

Almost surely, 249712069573 is an apocalyptic number.

It is an amenable number.

49712069573 is a deficient number, since it is larger than the sum of its proper divisors (1).

49712069573 is an equidigital number, since it uses as much as digits as its factorization.

49712069573 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2857680, while the sum is 53.

The spelling of 49712069573 in words is "forty-nine billion, seven hundred twelve million, sixty-nine thousand, five hundred seventy-three".