Base | Representation |
---|---|
bin | 101110010011000110… |
… | …000111001000111111 |
3 | 11202022112211022022212 |
4 | 232103012013020333 |
5 | 1303302344234434 |
6 | 34500531131035 |
7 | 3406631135162 |
oct | 562306071077 |
9 | 152275738285 |
10 | 49712493119 |
11 | 1a0a0451963 |
12 | 9774743a7b |
13 | 48c3327503 |
14 | 259848dad9 |
15 | 145e5028ce |
hex | b9318723f |
49712493119 has 2 divisors, whose sum is σ = 49712493120. Its totient is φ = 49712493118.
The previous prime is 49712493101. The next prime is 49712493121. The reversal of 49712493119 is 91139421794.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 49712493119 - 224 = 49695715903 is a prime.
It is a super-2 number, since 2×497124931192 (a number of 22 digits) contains 22 as substring.
It is a Sophie Germain prime.
Together with 49712493121, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49712493139) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24856246559 + 24856246560.
It is an arithmetic number, because the mean of its divisors is an integer number (24856246560).
Almost surely, 249712493119 is an apocalyptic number.
49712493119 is a deficient number, since it is larger than the sum of its proper divisors (1).
49712493119 is an equidigital number, since it uses as much as digits as its factorization.
49712493119 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 489888, while the sum is 50.
The spelling of 49712493119 in words is "forty-nine billion, seven hundred twelve million, four hundred ninety-three thousand, one hundred nineteen".
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