Base | Representation |
---|---|
bin | 10110100111010110101101… |
… | …00000100010111110110111 |
3 | 20112002012201002112121111022 |
4 | 23103223112200202332313 |
5 | 23004242013413143312 |
6 | 253433552043131355 |
7 | 13321632566105225 |
oct | 1323532640427667 |
9 | 215065632477438 |
10 | 49730730209207 |
11 | 149337587a8903 |
12 | 56b2194b13b5b |
13 | 2199784344b18 |
14 | c3cda18adb15 |
15 | 5b3925268172 |
hex | 2d3ad6822fb7 |
49730730209207 has 2 divisors, whose sum is σ = 49730730209208. Its totient is φ = 49730730209206.
The previous prime is 49730730209191. The next prime is 49730730209287. The reversal of 49730730209207 is 70290203703794.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 49730730209207 - 24 = 49730730209191 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49730730209287) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24865365104603 + 24865365104604.
It is an arithmetic number, because the mean of its divisors is an integer number (24865365104604).
Almost surely, 249730730209207 is an apocalyptic number.
49730730209207 is a deficient number, since it is larger than the sum of its proper divisors (1).
49730730209207 is an equidigital number, since it uses as much as digits as its factorization.
49730730209207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4000752, while the sum is 53.
The spelling of 49730730209207 in words is "forty-nine trillion, seven hundred thirty billion, seven hundred thirty million, two hundred nine thousand, two hundred seven".
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