Base | Representation |
---|---|
bin | 101110010111001111… |
… | …110001100101011101 |
3 | 11202111101212111012201 |
4 | 232113033301211131 |
5 | 1303423211311013 |
6 | 34511455531501 |
7 | 3411435111133 |
oct | 562717614535 |
9 | 152441774181 |
10 | 49782135133 |
11 | 1a126798a45 |
12 | 9793b29b91 |
13 | 490489c0c3 |
14 | 25a381b753 |
15 | 14656ac3dd |
hex | b973f195d |
49782135133 has 2 divisors, whose sum is σ = 49782135134. Its totient is φ = 49782135132.
The previous prime is 49782135131. The next prime is 49782135187. The reversal of 49782135133 is 33153128794.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 38558427769 + 11223707364 = 196363^2 + 105942^2 .
It is a cyclic number.
It is not a de Polignac number, because 49782135133 - 21 = 49782135131 is a prime.
Together with 49782135131, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49782135131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24891067566 + 24891067567.
It is an arithmetic number, because the mean of its divisors is an integer number (24891067567).
Almost surely, 249782135133 is an apocalyptic number.
It is an amenable number.
49782135133 is a deficient number, since it is larger than the sum of its proper divisors (1).
49782135133 is an equidigital number, since it uses as much as digits as its factorization.
49782135133 is an evil number, because the sum of its binary digits is even.
The product of its digits is 544320, while the sum is 46.
The spelling of 49782135133 in words is "forty-nine billion, seven hundred eighty-two million, one hundred thirty-five thousand, one hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •