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49822527257 is a prime number
BaseRepresentation
bin101110011001101001…
…110110111100011001
311202121012212121210022
4232121221312330121
51304014031333012
634515501400225
73412435331336
oct563151667431
9152535777708
1049822527257
111a147577168
1297a5569075
134910072279
1425a8d3398d
151468eda472
hexb99a76f19

49822527257 has 2 divisors, whose sum is σ = 49822527258. Its totient is φ = 49822527256.

The previous prime is 49822527233. The next prime is 49822527259. The reversal of 49822527257 is 75272522894.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 37505744896 + 12316782361 = 193664^2 + 110981^2 .

It is a cyclic number.

It is not a de Polignac number, because 49822527257 - 212 = 49822523161 is a prime.

Together with 49822527259, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 49822527199 and 49822527208.

It is not a weakly prime, because it can be changed into another prime (49822527259) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24911263628 + 24911263629.

It is an arithmetic number, because the mean of its divisors is an integer number (24911263629).

Almost surely, 249822527257 is an apocalyptic number.

It is an amenable number.

49822527257 is a deficient number, since it is larger than the sum of its proper divisors (1).

49822527257 is an equidigital number, since it uses as much as digits as its factorization.

49822527257 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5644800, while the sum is 53.

The spelling of 49822527257 in words is "forty-nine billion, eight hundred twenty-two million, five hundred twenty-seven thousand, two hundred fifty-seven".