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4983388453 is a prime number
BaseRepresentation
bin1001010010000100…
…00111100100100101
3110212022010100210201
410221002013210211
540201221412303
62142255150501
7234331050211
oct45102074445
913768110721
104983388453
112127aa155a
12b70b15431
13615593884
14353bb9941
151e277481d
hex129087925

4983388453 has 2 divisors, whose sum is σ = 4983388454. Its totient is φ = 4983388452.

The previous prime is 4983388451. The next prime is 4983388489. The reversal of 4983388453 is 3548833894.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4072737124 + 910651329 = 63818^2 + 30177^2 .

It is a cyclic number.

It is not a de Polignac number, because 4983388453 - 21 = 4983388451 is a prime.

Together with 4983388451, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 4983388394 and 4983388403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4983388451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2491694226 + 2491694227.

It is an arithmetic number, because the mean of its divisors is an integer number (2491694227).

Almost surely, 24983388453 is an apocalyptic number.

It is an amenable number.

4983388453 is a deficient number, since it is larger than the sum of its proper divisors (1).

4983388453 is an equidigital number, since it uses as much as digits as its factorization.

4983388453 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 9953280, while the sum is 55.

The square root of 4983388453 is about 70593.1190201991. The cubic root of 4983388453 is about 1708.0801559358.

The spelling of 4983388453 in words is "four billion, nine hundred eighty-three million, three hundred eighty-eight thousand, four hundred fifty-three".