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4993294541 is a prime number
BaseRepresentation
bin1001010011001111…
…11010000011001101
3110212222202122101212
410221213322003031
540211240411131
62143251344205
7234511206014
oct45147720315
913788678355
104993294541
112132648104
12b742b2065
13617651771
14355237a7b
151e357ea2b
hex1299fa0cd

4993294541 has 2 divisors, whose sum is σ = 4993294542. Its totient is φ = 4993294540.

The previous prime is 4993294499. The next prime is 4993294543. The reversal of 4993294541 is 1454923994.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4980124900 + 13169641 = 70570^2 + 3629^2 .

It is a cyclic number.

It is not a de Polignac number, because 4993294541 - 218 = 4993032397 is a prime.

Together with 4993294543, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 4993294541.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4993294543) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2496647270 + 2496647271.

It is an arithmetic number, because the mean of its divisors is an integer number (2496647271).

Almost surely, 24993294541 is an apocalyptic number.

It is an amenable number.

4993294541 is a deficient number, since it is larger than the sum of its proper divisors (1).

4993294541 is an equidigital number, since it uses as much as digits as its factorization.

4993294541 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1399680, while the sum is 50.

The square root of 4993294541 is about 70663.2474558027. The cubic root of 4993294541 is about 1709.2111931331.

The spelling of 4993294541 in words is "four billion, nine hundred ninety-three million, two hundred ninety-four thousand, five hundred forty-one".