Base | Representation |
---|---|
bin | 100100010111111000001… |
… | …1100000100001010011111 |
3 | 122200220111112120200101020 |
4 | 1020233300130010022133 |
5 | 1123401104144313200 |
6 | 14344313540015223 |
7 | 1024112612102532 |
oct | 110576034041237 |
9 | 18626445520336 |
10 | 4999080854175 |
11 | 16581098a8711 |
12 | 688a32091513 |
13 | 2a35468261b5 |
14 | 133d57684a19 |
15 | 8a086bb1ea0 |
hex | 48bf070429f |
4999080854175 has 24 divisors (see below), whose sum is σ = 8285355246480. Its totient is φ = 2659657670400.
The previous prime is 4999080854167. The next prime is 4999080854197. The reversal of 4999080854175 is 5714580809994.
4999080854175 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 4999080854175 - 23 = 4999080854167 is a prime.
It is a super-2 number, since 2×49990808541752 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 81453936 + ... + 81515285.
It is an arithmetic number, because the mean of its divisors is an integer number (345223135270).
Almost surely, 24999080854175 is an apocalyptic number.
4999080854175 is a deficient number, since it is larger than the sum of its proper divisors (3286274392305).
4999080854175 is a wasteful number, since it uses less digits than its factorization.
4999080854175 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 162969643 (or 162969638 counting only the distinct ones).
The product of its (nonzero) digits is 130636800, while the sum is 69.
The spelling of 4999080854175 in words is "four trillion, nine hundred ninety-nine billion, eighty million, eight hundred fifty-four thousand, one hundred seventy-five".
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