Base | Representation |
---|---|
bin | 1110100011100100001… |
… | …10001100000101101101 |
3 | 1202210220221122022101221 |
4 | 13101302012030011231 |
5 | 31143231342300331 |
6 | 1021431242503341 |
7 | 51063461344552 |
oct | 7216206140555 |
9 | 1683827568357 |
10 | 500130431341 |
11 | 1831166544a2 |
12 | 80b18804b51 |
13 | 38215187998 |
14 | 1a2c6696a29 |
15 | d0222e9711 |
hex | 747218c16d |
500130431341 has 2 divisors, whose sum is σ = 500130431342. Its totient is φ = 500130431340.
The previous prime is 500130431291. The next prime is 500130431387. The reversal of 500130431341 is 143134031005.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 467650822500 + 32479608841 = 683850^2 + 180221^2 .
It is a cyclic number.
It is not a de Polignac number, because 500130431341 - 29 = 500130430829 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (500137431341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 250065215670 + 250065215671.
It is an arithmetic number, because the mean of its divisors is an integer number (250065215671).
Almost surely, 2500130431341 is an apocalyptic number.
It is an amenable number.
500130431341 is a deficient number, since it is larger than the sum of its proper divisors (1).
500130431341 is an equidigital number, since it uses as much as digits as its factorization.
500130431341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 500130431341 its reverse (143134031005), we get a palindrome (643264462346).
The spelling of 500130431341 in words is "five hundred billion, one hundred thirty million, four hundred thirty-one thousand, three hundred forty-one".
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