Base | Representation |
---|---|
bin | 10110101111100101001000… |
… | …00101001010011001000111 |
3 | 20120002020012111022201101012 |
4 | 23113302210011022121013 |
5 | 23023404321103330320 |
6 | 254211452225152435 |
7 | 13351226325560636 |
oct | 1327624405123107 |
9 | 216066174281335 |
10 | 50013352011335 |
11 | 14a325a84018a9 |
12 | 5738b0a48b71b |
13 | 21ba314a034bb |
14 | c4c932a0551d |
15 | 5bae66e464c5 |
hex | 2d7ca414a647 |
50013352011335 has 48 divisors (see below), whose sum is σ = 61920893754720. Its totient is φ = 38756350586880.
The previous prime is 50013352011331. The next prime is 50013352011379. The reversal of 50013352011335 is 53311025331005.
It is not a de Polignac number, because 50013352011335 - 22 = 50013352011331 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (50013352011331) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 4353145271 + ... + 4353156759.
It is an arithmetic number, because the mean of its divisors is an integer number (1290018619890).
Almost surely, 250013352011335 is an apocalyptic number.
50013352011335 is a deficient number, since it is larger than the sum of its proper divisors (11907541743385).
50013352011335 is a wasteful number, since it uses less digits than its factorization.
50013352011335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12368 (or 12105 counting only the distinct ones).
The product of its (nonzero) digits is 20250, while the sum is 32.
The spelling of 50013352011335 in words is "fifty trillion, thirteen billion, three hundred fifty-two million, eleven thousand, three hundred thirty-five".
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