Search a number
-
+
50021197807517 is a prime number
BaseRepresentation
bin10110101111110011101111…
…01110011111111110011101
320120002222110021120110101222
423113321313232133332131
523024021403114320032
6254215230535543125
713351624625002166
oct1327716756377635
9216088407513358
1050021197807517
1114a35964126682
12573a539b2aaa5
1321bac95305151
14c4d078a0c76d
155bb275b31a12
hex2d7e77b9ff9d

50021197807517 has 2 divisors, whose sum is σ = 50021197807518. Its totient is φ = 50021197807516.

The previous prime is 50021197807513. The next prime is 50021197807573. The reversal of 50021197807517 is 71570879112005.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 48824611226521 + 1196586580996 = 6987461^2 + 1093886^2 .

It is a cyclic number.

It is not a de Polignac number, because 50021197807517 - 22 = 50021197807513 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (50021197807513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25010598903758 + 25010598903759.

It is an arithmetic number, because the mean of its divisors is an integer number (25010598903759).

Almost surely, 250021197807517 is an apocalyptic number.

It is an amenable number.

50021197807517 is a deficient number, since it is larger than the sum of its proper divisors (1).

50021197807517 is an equidigital number, since it uses as much as digits as its factorization.

50021197807517 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1234800, while the sum is 53.

The spelling of 50021197807517 in words is "fifty trillion, twenty-one billion, one hundred ninety-seven million, eight hundred seven thousand, five hundred seventeen".