Base | Representation |
---|---|
bin | 101110100110001101… |
… | …010000100111001111 |
3 | 11210010220011112222012 |
4 | 232212031100213033 |
5 | 1304431440242111 |
6 | 34552423411435 |
7 | 3420603423266 |
oct | 564615204717 |
9 | 153126145865 |
10 | 50033134031 |
11 | 1a245444151 |
12 | 9843bb3b7b |
13 | 49448a136a |
14 | 25c8cb75dd |
15 | 147c73c48b |
hex | ba63509cf |
50033134031 has 2 divisors, whose sum is σ = 50033134032. Its totient is φ = 50033134030.
The previous prime is 50033133947. The next prime is 50033134037. The reversal of 50033134031 is 13043133005.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50033134031 is a prime.
It is a super-2 number, since 2×500331340312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 50033133988 and 50033134006.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50033134037) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25016567015 + 25016567016.
It is an arithmetic number, because the mean of its divisors is an integer number (25016567016).
Almost surely, 250033134031 is an apocalyptic number.
50033134031 is a deficient number, since it is larger than the sum of its proper divisors (1).
50033134031 is an equidigital number, since it uses as much as digits as its factorization.
50033134031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1620, while the sum is 23.
Adding to 50033134031 its reverse (13043133005), we get a palindrome (63076267036).
The spelling of 50033134031 in words is "fifty billion, thirty-three million, one hundred thirty-four thousand, thirty-one".
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