Base | Representation |
---|---|
bin | 10110110000101111100011… |
… | …10100110000111101001001 |
3 | 20120020001100022021202121221 |
4 | 23120113301310300331021 |
5 | 23030033140111310403 |
6 | 254242101302002041 |
7 | 13354142464663504 |
oct | 1330276164607511 |
9 | 216201308252557 |
10 | 50053311041353 |
11 | 14a48543217554 |
12 | 5744800716321 |
13 | 21c101243c869 |
14 | c5084398a13b |
15 | 5bc005038dbd |
hex | 2d85f1d30f49 |
50053311041353 has 2 divisors, whose sum is σ = 50053311041354. Its totient is φ = 50053311041352.
The previous prime is 50053311041317. The next prime is 50053311041429. The reversal of 50053311041353 is 35314011335005.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 50021274695184 + 32036346169 = 7072572^2 + 178987^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50053311041353 is a prime.
It is not a weakly prime, because it can be changed into another prime (50053311041303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25026655520676 + 25026655520677.
It is an arithmetic number, because the mean of its divisors is an integer number (25026655520677).
Almost surely, 250053311041353 is an apocalyptic number.
It is an amenable number.
50053311041353 is a deficient number, since it is larger than the sum of its proper divisors (1).
50053311041353 is an equidigital number, since it uses as much as digits as its factorization.
50053311041353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40500, while the sum is 34.
Adding to 50053311041353 its reverse (35314011335005), we get a palindrome (85367322376358).
The spelling of 50053311041353 in words is "fifty trillion, fifty-three billion, three hundred eleven million, forty-one thousand, three hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •