Base | Representation |
---|---|
bin | 10110110000110001000101… |
… | …10100010011011001011111 |
3 | 20120020010110120221210020011 |
4 | 23120120202310103121133 |
5 | 23030041331022110441 |
6 | 254242315023304051 |
7 | 13354202035361623 |
oct | 1330304264233137 |
9 | 216203416853204 |
10 | 50054133003871 |
11 | 14a48925199117 |
12 | 57449aba4b027 |
13 | 21c1113812209 |
14 | c508c0bd1183 |
15 | 5bc05229d581 |
hex | 2d8622d1365f |
50054133003871 has 2 divisors, whose sum is σ = 50054133003872. Its totient is φ = 50054133003870.
The previous prime is 50054133003851. The next prime is 50054133003913. The reversal of 50054133003871 is 17830033145005.
It is a happy number.
50054133003871 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 50054133003871 - 29 = 50054133003359 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50054133003841) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25027066501935 + 25027066501936.
It is an arithmetic number, because the mean of its divisors is an integer number (25027066501936).
Almost surely, 250054133003871 is an apocalyptic number.
50054133003871 is a deficient number, since it is larger than the sum of its proper divisors (1).
50054133003871 is an equidigital number, since it uses as much as digits as its factorization.
50054133003871 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 151200, while the sum is 40.
Adding to 50054133003871 its reverse (17830033145005), we get a palindrome (67884166148876).
The spelling of 50054133003871 in words is "fifty trillion, fifty-four billion, one hundred thirty-three million, three thousand, eight hundred seventy-one".
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