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50088036411047 is a prime number
BaseRepresentation
bin10110110001110000001111…
…00111100010011010100111
320120100100222101012022121102
423120320013213202122213
523031120244310123142
6254310043135110315
713356512143522415
oct1330700747423247
9216310871168542
1050088036411047
1114a61242841798
12574b49207239b
1321c43877a8cab
14c523b98082b5
155bcd8891c532
hex2d8e079e26a7

50088036411047 has 2 divisors, whose sum is σ = 50088036411048. Its totient is φ = 50088036411046.

The previous prime is 50088036410987. The next prime is 50088036411071. The reversal of 50088036411047 is 74011463088005.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 50088036411047 - 28 = 50088036410791 is a prime.

It is a super-2 number, since 2×500880364110472 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 50088036410992 and 50088036411010.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (50088036410047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25044018205523 + 25044018205524.

It is an arithmetic number, because the mean of its divisors is an integer number (25044018205524).

Almost surely, 250088036411047 is an apocalyptic number.

50088036411047 is a deficient number, since it is larger than the sum of its proper divisors (1).

50088036411047 is an equidigital number, since it uses as much as digits as its factorization.

50088036411047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 645120, while the sum is 47.

The spelling of 50088036411047 in words is "fifty trillion, eighty-eight billion, thirty-six million, four hundred eleven thousand, forty-seven".