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50102111300 = 2252501021113
BaseRepresentation
bin101110101010010100…
…011000110001000100
311210022200221221222212
4232222110120301010
51310102120030200
635003330042552
73422401630223
oct565224306104
9153280857885
1050102111300
111a28037685a
129863119458
134955c72507
1425d4110cba
151483815035
hexbaa518c44

50102111300 has 18 divisors (see below), whose sum is σ = 108721581738. Its totient is φ = 20040844480.

The previous prime is 50102111299. The next prime is 50102111407. The reversal of 50102111300 is 311120105.

It can be written as a sum of positive squares in 3 ways, for example, as 4145041924 + 45957069376 = 64382^2 + 214376^2 .

It is a super-3 number, since 3×501021113003 (a number of 33 digits) contains 333 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 250510457 + ... + 250510656.

Almost surely, 250102111300 is an apocalyptic number.

50102111300 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

50102111300 is an abundant number, since it is smaller than the sum of its proper divisors (58619470438).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

50102111300 is a wasteful number, since it uses less digits than its factorization.

50102111300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 501021127 (or 501021120 counting only the distinct ones).

The product of its (nonzero) digits is 30, while the sum is 14.

Adding to 50102111300 its reverse (311120105), we get a palindrome (50413231405).

The spelling of 50102111300 in words is "fifty billion, one hundred two million, one hundred eleven thousand, three hundred".

Divisors: 1 2 4 5 10 20 25 50 100 501021113 1002042226 2004084452 2505105565 5010211130 10020422260 12525527825 25051055650 50102111300