Base | Representation |
---|---|
bin | 1001010101010001… |
… | …11010000110100101 |
3 | 110221011211100022021 |
4 | 10222220322012211 |
5 | 40230121142432 |
6 | 2145100503141 |
7 | 235106065045 |
oct | 45250720645 |
9 | 13834740267 |
10 | 5010334117 |
11 | 21412261a8 |
12 | b79b4aab1 |
13 | 61b039559 |
14 | 3575d1725 |
15 | 1e4ce8697 |
hex | 12aa3a1a5 |
5010334117 has 2 divisors, whose sum is σ = 5010334118. Its totient is φ = 5010334116.
The previous prime is 5010334081. The next prime is 5010334123. The reversal of 5010334117 is 7114330105.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3883657761 + 1126676356 = 62319^2 + 33566^2 .
It is a cyclic number.
It is not a de Polignac number, because 5010334117 - 211 = 5010332069 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5010334091 and 5010334100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5010334517) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2505167058 + 2505167059.
It is an arithmetic number, because the mean of its divisors is an integer number (2505167059).
Almost surely, 25010334117 is an apocalyptic number.
It is an amenable number.
5010334117 is a deficient number, since it is larger than the sum of its proper divisors (1).
5010334117 is an equidigital number, since it uses as much as digits as its factorization.
5010334117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1260, while the sum is 25.
The square root of 5010334117 is about 70783.7136423344. The cubic root of 5010334117 is about 1711.1532087512.
The spelling of 5010334117 in words is "five billion, ten million, three hundred thirty-four thousand, one hundred seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.085 sec. • engine limits •