Base | Representation |
---|---|
bin | 101110101011100001… |
… | …010000001011011101 |
3 | 11210101002212200110221 |
4 | 232223201100023131 |
5 | 1310122244324323 |
6 | 35005330001341 |
7 | 3423035122303 |
oct | 565341201335 |
9 | 153332780427 |
10 | 50122261213 |
11 | 1a290789782 |
12 | 9869a16251 |
13 | 495a1a8c3b |
14 | 25d6a78273 |
15 | 148549555d |
hex | bab8502dd |
50122261213 has 2 divisors, whose sum is σ = 50122261214. Its totient is φ = 50122261212.
The previous prime is 50122261207. The next prime is 50122261243. The reversal of 50122261213 is 31216222105.
50122261213 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 42426936484 + 7695324729 = 205978^2 + 87723^2 .
It is a cyclic number.
It is not a de Polignac number, because 50122261213 - 217 = 50122130141 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50122261243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25061130606 + 25061130607.
It is an arithmetic number, because the mean of its divisors is an integer number (25061130607).
Almost surely, 250122261213 is an apocalyptic number.
It is an amenable number.
50122261213 is a deficient number, since it is larger than the sum of its proper divisors (1).
50122261213 is an equidigital number, since it uses as much as digits as its factorization.
50122261213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 50122261213 its reverse (31216222105), we get a palindrome (81338483318).
The spelling of 50122261213 in words is "fifty billion, one hundred twenty-two million, two hundred sixty-one thousand, two hundred thirteen".
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