Base | Representation |
---|---|
bin | 100100011110000011000… |
… | …1101011100010001101101 |
3 | 122202011200222002220210021 |
4 | 1020330012031130101231 |
5 | 1124110223220141141 |
6 | 14354344425042141 |
7 | 1025062143466663 |
oct | 110740615342155 |
9 | 18664628086707 |
10 | 5012331021421 |
11 | 1662799210459 |
12 | 68b50b626351 |
13 | 2a4878998749 |
14 | 134853330c33 |
15 | 8a5b007c6d1 |
hex | 48f0635c46d |
5012331021421 has 2 divisors, whose sum is σ = 5012331021422. Its totient is φ = 5012331021420.
The previous prime is 5012331021349. The next prime is 5012331021479. The reversal of 5012331021421 is 1241201332105.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4819829458921 + 192501562500 = 2195411^2 + 438750^2 .
It is a cyclic number.
It is not a de Polignac number, because 5012331021421 - 27 = 5012331021293 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5012331021521) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2506165510710 + 2506165510711.
It is an arithmetic number, because the mean of its divisors is an integer number (2506165510711).
Almost surely, 25012331021421 is an apocalyptic number.
It is an amenable number.
5012331021421 is a deficient number, since it is larger than the sum of its proper divisors (1).
5012331021421 is an equidigital number, since it uses as much as digits as its factorization.
5012331021421 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 5012331021421 its reverse (1241201332105), we get a palindrome (6253532353526).
The spelling of 5012331021421 in words is "five trillion, twelve billion, three hundred thirty-one million, twenty-one thousand, four hundred twenty-one".
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