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5012331021421 is a prime number
BaseRepresentation
bin100100011110000011000…
…1101011100010001101101
3122202011200222002220210021
41020330012031130101231
51124110223220141141
614354344425042141
71025062143466663
oct110740615342155
918664628086707
105012331021421
111662799210459
1268b50b626351
132a4878998749
14134853330c33
158a5b007c6d1
hex48f0635c46d

5012331021421 has 2 divisors, whose sum is σ = 5012331021422. Its totient is φ = 5012331021420.

The previous prime is 5012331021349. The next prime is 5012331021479. The reversal of 5012331021421 is 1241201332105.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4819829458921 + 192501562500 = 2195411^2 + 438750^2 .

It is a cyclic number.

It is not a de Polignac number, because 5012331021421 - 27 = 5012331021293 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5012331021521) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2506165510710 + 2506165510711.

It is an arithmetic number, because the mean of its divisors is an integer number (2506165510711).

Almost surely, 25012331021421 is an apocalyptic number.

It is an amenable number.

5012331021421 is a deficient number, since it is larger than the sum of its proper divisors (1).

5012331021421 is an equidigital number, since it uses as much as digits as its factorization.

5012331021421 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 5012331021421 its reverse (1241201332105), we get a palindrome (6253532353526).

The spelling of 5012331021421 in words is "five trillion, twelve billion, three hundred thirty-one million, twenty-one thousand, four hundred twenty-one".