Base | Representation |
---|---|
bin | 101110101100000000… |
… | …011010110100010011 |
3 | 11210101200020202122221 |
4 | 232230000122310103 |
5 | 1310131342300001 |
6 | 35010221041511 |
7 | 3423164430535 |
oct | 565400326423 |
9 | 153350222587 |
10 | 50130431251 |
11 | 1a295359a7a |
12 | 98706b6297 |
13 | 495baa9894 |
14 | 25d7ba3855 |
15 | 148605b1a1 |
hex | bac01ad13 |
50130431251 has 2 divisors, whose sum is σ = 50130431252. Its totient is φ = 50130431250.
The previous prime is 50130431227. The next prime is 50130431279. The reversal of 50130431251 is 15213403105.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 50130431251 - 213 = 50130423059 is a prime.
It is a super-2 number, since 2×501304312512 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (50130431291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25065215625 + 25065215626.
It is an arithmetic number, because the mean of its divisors is an integer number (25065215626).
Almost surely, 250130431251 is an apocalyptic number.
50130431251 is a deficient number, since it is larger than the sum of its proper divisors (1).
50130431251 is an equidigital number, since it uses as much as digits as its factorization.
50130431251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1800, while the sum is 25.
Adding to 50130431251 its reverse (15213403105), we get a palindrome (65343834356).
The spelling of 50130431251 in words is "fifty billion, one hundred thirty million, four hundred thirty-one thousand, two hundred fifty-one".
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