Base | Representation |
---|---|
bin | 101110101100000100… |
… | …001110110000011111 |
3 | 11210101202010112021121 |
4 | 232230010032300133 |
5 | 1310132121233211 |
6 | 35010254311411 |
7 | 3423206061565 |
oct | 565404166037 |
9 | 153352115247 |
10 | 50131430431 |
11 | 1a295981745 |
12 | 9870ab8567 |
13 | 495c069604 |
14 | 25d7d83a35 |
15 | 14861a7271 |
hex | bac10ec1f |
50131430431 has 2 divisors, whose sum is σ = 50131430432. Its totient is φ = 50131430430.
The previous prime is 50131430389. The next prime is 50131430467. The reversal of 50131430431 is 13403413105.
50131430431 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 50131430431 - 215 = 50131397663 is a prime.
It is a super-2 number, since 2×501314304312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 50131430396 and 50131430405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50131430231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25065715215 + 25065715216.
It is an arithmetic number, because the mean of its divisors is an integer number (25065715216).
Almost surely, 250131430431 is an apocalyptic number.
50131430431 is a deficient number, since it is larger than the sum of its proper divisors (1).
50131430431 is an equidigital number, since it uses as much as digits as its factorization.
50131430431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 50131430431 its reverse (13403413105), we get a palindrome (63534843536).
The spelling of 50131430431 in words is "fifty billion, one hundred thirty-one million, four hundred thirty thousand, four hundred thirty-one".
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