Base | Representation |
---|---|
bin | 100100011111011011101… |
… | …1011011000011101001111 |
3 | 122202110101011202020001212 |
4 | 1020332313123120131033 |
5 | 1124132320341234043 |
6 | 14355555435325035 |
7 | 1025225625452354 |
oct | 110766733303517 |
9 | 18673334666055 |
10 | 5015304243023 |
11 | 1663a84550898 |
12 | 68bbbb2b077b |
13 | 2a4c30965479 |
14 | 134a5616662b |
15 | 8a6d60d2018 |
hex | 48fb76d874f |
5015304243023 has 2 divisors, whose sum is σ = 5015304243024. Its totient is φ = 5015304243022.
The previous prime is 5015304242983. The next prime is 5015304243029. The reversal of 5015304243023 is 3203424035105.
5015304243023 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5015304243023 - 218 = 5015303980879 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5015304243029) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2507652121511 + 2507652121512.
It is an arithmetic number, because the mean of its divisors is an integer number (2507652121512).
Almost surely, 25015304243023 is an apocalyptic number.
5015304243023 is a deficient number, since it is larger than the sum of its proper divisors (1).
5015304243023 is an equidigital number, since it uses as much as digits as its factorization.
5015304243023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43200, while the sum is 32.
Adding to 5015304243023 its reverse (3203424035105), we get a palindrome (8218728278128).
The spelling of 5015304243023 in words is "five trillion, fifteen billion, three hundred four million, two hundred forty-three thousand, twenty-three".
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